new problem done

problems/1409/main.py

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+class Solution:
+    def processQueries(self, queries, m):
+        perm = []
+        result = []
+        for i in range(1, m + 1):
+            perm.append(i)
+            
+        for q in queries:
+            pos = perm.index(q)
+            result.append(pos)
+            perm = [q] + perm[0:pos] + perm[pos + 1:]
+            
+        return result
+
+s = Solution()
+print("Expected: [2, 1, 2, 1]")
+print("Got:", s.processQueries([3,1,2,1], 5))

problems/1409/problem.txt

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+Given the array queries of positive integers between 1 and m, you have to process all queries[i] (from i=0 to i=queries.length-1) according to the following rules:
+
+    In the beginning, you have the permutation P=[1,2,3,...,m].
+    For the current i, find the position of queries[i] in the permutation P (indexing from 0) and then move this at the beginning of the permutation P. Notice that the position of queries[i] in P is the result for queries[i].
+
+Return an array containing the result for the given queries.
+
+ 
+
+Example 1:
+
+Input: queries = [3,1,2,1], m = 5
+Output: [2,1,2,1] 
+Explanation: The queries are processed as follow: 
+For i=0: queries[i]=3, P=[1,2,3,4,5], position of 3 in P is 2, then we move 3 to the beginning of P resulting in P=[3,1,2,4,5]. 
+For i=1: queries[i]=1, P=[3,1,2,4,5], position of 1 in P is 1, then we move 1 to the beginning of P resulting in P=[1,3,2,4,5]. 
+For i=2: queries[i]=2, P=[1,3,2,4,5], position of 2 in P is 2, then we move 2 to the beginning of P resulting in P=[2,1,3,4,5]. 
+For i=3: queries[i]=1, P=[2,1,3,4,5], position of 1 in P is 1, then we move 1 to the beginning of P resulting in P=[1,2,3,4,5]. 
+Therefore, the array containing the result is [2,1,2,1].  
+
+Example 2:
+
+Input: queries = [4,1,2,2], m = 4
+Output: [3,1,2,0]
+
+Example 3:
+
+Input: queries = [7,5,5,8,3], m = 8
+Output: [6,5,0,7,5]
+
+ 
+
+Constraints:
+
+    1 <= m <= 10^3
+    1 <= queries.length <= m
+    1 <= queries[i] <= m
+

problems/1409/run.sh

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+#!/bin/bash
+
+python3 main.py