Another problem done

804/main.py

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+class Solution:
+    def uniqueMorseRepresentations(self, words):
+        transforms = dict()
+        for word in words:
+            t = ""
+            for c in word:
+                t += self.morseFromChar(c)
+            transforms[t] = True
+            
+        return len(transforms.keys())
+                
+        
+    def morseFromChar(self, c):
+        morseMap = [".-","-...","-.-.","-..",".","..-.","--.","....","..",".---","-.-",".-..","--","-.","---",".--.","--.-",".-.","...","-","..-","...-",".--","-..-","-.--","--.."]
+        return morseMap[ord(c)-97]
+
+s = Solution()
+print("Expected: 2")
+print("Got:", s.uniqueMorseRepresentations(["gin", "zen", "gig", "msg"]))

804/problem.txt

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+International Morse Code defines a standard encoding where each letter is mapped to a series of dots and dashes, as follows: "a" maps to ".-", "b" maps to "-...", "c" maps to "-.-.", and so on.
+
+For convenience, the full table for the 26 letters of the English alphabet is given below:
+
+[".-","-...","-.-.","-..",".","..-.","--.","....","..",".---","-.-",".-..","--","-.","---",".--.","--.-",".-.","...","-","..-","...-",".--","-..-","-.--","--.."]
+
+Now, given a list of words, each word can be written as a concatenation of the Morse code of each letter. For example, "cba" can be written as "-.-..--...", (which is the concatenation "-.-." + "-..." + ".-"). We'll call such a concatenation, the transformation of a word.
+
+Return the number of different transformations among all words we have.
+
+Example:
+Input: words = ["gin", "zen", "gig", "msg"]
+Output: 2
+Explanation: 
+The transformation of each word is:
+"gin" -> "--...-."
+"zen" -> "--...-."
+"gig" -> "--...--."
+"msg" -> "--...--."
+
+There are 2 different transformations, "--...-." and "--...--.".
+
+Note:
+
+    The length of words will be at most 100.
+    Each words[i] will have length in range [1, 12].
+    words[i] will only consist of lowercase letters.
+

804/run.sh

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+#!/bin/bash
+
+python3 main.py