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The power of an integer x is defined as the number of steps needed to transform x into 1 using the following steps: |
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if x is even then x = x / 2 |
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if x is odd then x = 3 * x + 1 |
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For example, the power of x = 3 is 7 because 3 needs 7 steps to become 1 (3 --> 10 --> 5 --> 16 --> 8 --> 4 --> 2 --> 1). |
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Given three integers lo, hi and k. The task is to sort all integers in the interval [lo, hi] by the power value in ascending order, if two or more integers have the same power value sort them by ascending order. |
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Return the k-th integer in the range [lo, hi] sorted by the power value. |
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Notice that for any integer x (lo <= x <= hi) it is guaranteed that x will transform into 1 using these steps and that the power of x is will fit in 32 bit signed integer. |
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Example 1: |
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Input: lo = 12, hi = 15, k = 2 |
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Output: 13 |
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Explanation: The power of 12 is 9 (12 --> 6 --> 3 --> 10 --> 5 --> 16 --> 8 --> 4 --> 2 --> 1) |
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The power of 13 is 9 |
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The power of 14 is 17 |
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The power of 15 is 17 |
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The interval sorted by the power value [12,13,14,15]. For k = 2 answer is the second element which is 13. |
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Notice that 12 and 13 have the same power value and we sorted them in ascending order. Same for 14 and 15. |
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Example 2: |
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Input: lo = 1, hi = 1, k = 1 |
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Output: 1 |
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Example 3: |
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Input: lo = 7, hi = 11, k = 4 |
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Output: 7 |
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Explanation: The power array corresponding to the interval [7, 8, 9, 10, 11] is [16, 3, 19, 6, 14]. |
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The interval sorted by power is [8, 10, 11, 7, 9]. |
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The fourth number in the sorted array is 7. |
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Example 4: |
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Input: lo = 10, hi = 20, k = 5 |
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Output: 13 |
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Example 5: |
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Input: lo = 1, hi = 1000, k = 777 |
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Output: 570 |
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Constraints: |
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1 <= lo <= hi <= 1000 |
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1 <= k <= hi - lo + 1 |
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