Quellcode durchsuchen

Another one bites the dust

master
Lachlan Jacob vor 5 Jahren
Ursprung
Commit
fb92c4a350
3 geänderte Dateien mit 39 neuen und 0 gelöschten Zeilen
  1. 29
    0
      1379/main.py
  2. 7
    0
      1379/problem.txt
  3. 3
    0
      1379/run.sh

+ 29
- 0
1379/main.py Datei anzeigen

@@ -0,0 +1,29 @@
class TreeNode:
def __init__(self, x):
self.val = x
self.left = None
self.right = None

class Solution:
def getTargetCopy(self, original: TreeNode, cloned: TreeNode, target: TreeNode) -> TreeNode:
return self.findTarget(cloned, target)
def findTarget(self, tree, t):
if tree is not None:
if tree.val == t.val:
return tree
leftFound = self.findTarget(tree.left, t)
rightFound = self.findTarget(tree.right, t)
if leftFound is not None:
return leftFound
elif rightFound is not None:
return rightFound

s = Solution()
o = TreeNode(1)
o.left = TreeNode(3)
c = TreeNode(1)
t = TreeNode(3)
c.left = t
print("Expected: 3")
print("Got:", s.getTargetCopy(o, c, t).val)

+ 7
- 0
1379/problem.txt Datei anzeigen

@@ -0,0 +1,7 @@
Given two binary trees original and cloned and given a reference to a node target in the original tree.

The cloned tree is a copy of the original tree.

Return a reference to the same node in the cloned tree.

Note that you are not allowed to change any of the two trees or the target node and the answer must be a reference to a node in the cloned tree.

+ 3
- 0
1379/run.sh Datei anzeigen

@@ -0,0 +1,3 @@
#!/bin/bash

python3 main.py

Laden…
Abbrechen
Speichern