class Solution:
    def oddCells(self, n, m, indices):
        
        # Initialise the matrix
        matrix = []
        for x in range(n):
            new_row = []
            for y in range(m):
                new_row.append(0)
            matrix.append(new_row)
            
        # Now apply steps
        for i in indices:
            ri = i[0]
            ci = i[1]
            for n in range(len(matrix[ri])):
                matrix[ri][n] += 1
            for n in range(len(matrix)):
                matrix[n][ci] += 1
                
        # now count odd values (this could be done while changes are made, but this is easier to reason)
        count = 0
        for x in range(len(matrix)):
            for y in range(len(matrix[x])):
                if matrix[x][y] % 2 != 0:
                    count += 1
            
        return count

s = Solution()
print("Expected: 6")
print("Got:", s.oddCells(2, 3, [[0, 1], [1, 1]]))