My LeetCode grinding. Trying to do a problem a day.
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  1. Given a non-empty, singly linked list with head node head, return a middle node of linked list.
  2. If there are two middle nodes, return the second middle node.
  3. Example 1:
  4. Input: [1,2,3,4,5]
  5. Output: Node 3 from this list (Serialization: [3,4,5])
  6. The returned node has value 3. (The judge's serialization of this node is [3,4,5]).
  7. Note that we returned a ListNode object ans, such that:
  8. ans.val = 3, ans.next.val = 4, ans.next.next.val = 5, and ans.next.next.next = NULL.
  9. Example 2:
  10. Input: [1,2,3,4,5,6]
  11. Output: Node 4 from this list (Serialization: [4,5,6])
  12. Since the list has two middle nodes with values 3 and 4, we return the second one.
  13. Note:
  14. The number of nodes in the given list will be between 1 and 100.