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- Given n and m which are the dimensions of a matrix initialized by zeros and given an array indices where indices[i] = [ri, ci]. For each pair of [ri, ci] you have to increment all cells in row ri and column ci by 1.
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- Return the number of cells with odd values in the matrix after applying the increment to all indices.
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- (There was pictures here, but hopefully this is clear enough)
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- Example 1:
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- Input: n = 2, m = 3, indices = [[0,1],[1,1]]
- Output: 6
- Explanation: Initial matrix = [[0,0,0],[0,0,0]].
- After applying first increment it becomes [[1,2,1],[0,1,0]].
- The final matrix will be [[1,3,1],[1,3,1]] which contains 6 odd numbers.
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- Example 2:
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- Input: n = 2, m = 2, indices = [[1,1],[0,0]]
- Output: 0
- Explanation: Final matrix = [[2,2],[2,2]]. There is no odd number in the final matrix.
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- Constraints:
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- 1 <= n <= 50
- 1 <= m <= 50
- 1 <= indices.length <= 100
- 0 <= indices[i][0] < n
- 0 <= indices[i][1] < m
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