leetcode-grind/problems/844/main.py

# There is a better way to do this, try think a little more.
# Perhaps compare a char at a time? Need to be able to extend until the end of the string though.

class Solution:
    def backspaceCompare(self, S: str, T: str) -> bool:
        resS = ""
        for c in S:
            if c != '#':
                resS += c
            elif len(resS) > 0:
                resS = resS[0:len(resS) - 1]
        resT = ""
        for c in T:
            if c != '#':
                resT += c
            elif len(resT) > 0:
                resT = resT[0:len(resT) - 1]
        
        return resS == resT

s = Solution()
print("Expected: True")
print("Got:", s.backspaceCompare("xywrrmp", "xywrrmu#p"))