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Problem done with some speedy C

master
Lachlan Jacob 5年前
コミット
8a824a250e
3個のファイルの変更91行の追加0行の削除
  1. 46
    0
      problems/27/main.c
  2. 40
    0
      problems/27/problem.txt
  3. 5
    0
      problems/27/run.sh

+ 46
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problems/27/main.c ファイルの表示

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#include <stdio.h>
#include <stdlib.h>

void printArr(int* arr, int arrSize) {
printf("[");
for (int i = 0; i < arrSize; i++) {
printf(" %d ", arr[i]);
}
printf("]\n");
}

int removeElement(int* nums, int numsSize, int val) {
int endPointer = numsSize - 1;
int i = 0;
while (i < endPointer + 1) {
if (nums[i] == val) {
// Find a valid element to swap, if one is not found
// then return the current length
while (nums[endPointer] == val && endPointer > i) {
endPointer--;
}
if (endPointer == i) {
return i;
}
nums[i] = nums[endPointer--];
}
i++;
}
return i;
}

int main() {
int* arr = malloc(sizeof(int) * 8);
arr[0] = 0;
arr[1] = 1;
arr[2] = 2;
arr[3] = 2;
arr[4] = 3;
arr[5] = 0;
arr[6] = 4;
arr[7] = 2;
int result = removeElement(arr, 8, 2);
printf("Expected: [ 0 1 4 0 3 ]\nGot: ");
printArr(arr, result);
return 0;
}

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problems/27/problem.txt ファイルの表示

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Given an array nums and a value val, remove all instances of that value in-place and return the new length.

Do not allocate extra space for another array, you must do this by modifying the input array in-place with O(1) extra memory.

The order of elements can be changed. It doesn't matter what you leave beyond the new length.

Example 1:

Given nums = [3,2,2,3], val = 3,

Your function should return length = 2, with the first two elements of nums being 2.

It doesn't matter what you leave beyond the returned length.

Example 2:

Given nums = [0,1,2,2,3,0,4,2], val = 2,

Your function should return length = 5, with the first five elements of nums containing 0, 1, 3, 0, and 4.

Note that the order of those five elements can be arbitrary.

It doesn't matter what values are set beyond the returned length.

Clarification:

Confused why the returned value is an integer but your answer is an array?

Note that the input array is passed in by reference, which means modification to the input array will be known to the caller as well.

Internally you can think of this:

// nums is passed in by reference. (i.e., without making a copy)
int len = removeElement(nums, val);

// any modification to nums in your function would be known by the caller.
// using the length returned by your function, it prints the first len elements.
for (int i = 0; i < len; i++) {
print(nums[i]);
}

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problems/27/run.sh ファイルの表示

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#!/bin/bash

gcc -o main main.c
./main
rm main

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