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Given an array nums and a value val, remove all instances of that value in-place and return the new length. |
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Do not allocate extra space for another array, you must do this by modifying the input array in-place with O(1) extra memory. |
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The order of elements can be changed. It doesn't matter what you leave beyond the new length. |
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Example 1: |
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Given nums = [3,2,2,3], val = 3, |
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Your function should return length = 2, with the first two elements of nums being 2. |
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It doesn't matter what you leave beyond the returned length. |
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Example 2: |
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Given nums = [0,1,2,2,3,0,4,2], val = 2, |
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Your function should return length = 5, with the first five elements of nums containing 0, 1, 3, 0, and 4. |
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Note that the order of those five elements can be arbitrary. |
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It doesn't matter what values are set beyond the returned length. |
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Clarification: |
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Confused why the returned value is an integer but your answer is an array? |
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Note that the input array is passed in by reference, which means modification to the input array will be known to the caller as well. |
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Internally you can think of this: |
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// nums is passed in by reference. (i.e., without making a copy) |
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int len = removeElement(nums, val); |
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// any modification to nums in your function would be known by the caller. |
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// using the length returned by your function, it prints the first len elements. |
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for (int i = 0; i < len; i++) { |
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print(nums[i]); |
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} |