Another problem done

852/main.py

+class Solution:
+    def peakIndexInMountainArray(self, A):
+        # return the peak of the mountain... i.e Where the array starts going down in value
+        last = -1
+        for ind, n in enumerate(A):
+            if n < last:
+                return ind - 1
+            last = n
+
+        # This should never happen
+        return -1
+
+s = Solution()
+print("Expected: 1")
+print("Got:", s.peakIndexInMountainArray([0, 2, 1, 0]))

852/problem.txt

+Let's call an array A a mountain if the following properties hold:
+
+    A.length >= 3
+    There exists some 0 < i < A.length - 1 such that A[0] < A[1] < ... A[i-1] < A[i] > A[i+1] > ... > A[A.length - 1]
+
+Given an array that is definitely a mountain, return any i such that A[0] < A[1] < ... A[i-1] < A[i] > A[i+1] > ... > A[A.length - 1].
+
+Example 1:
+
+Input: [0,1,0]
+Output: 1
+
+Example 2:
+
+Input: [0,2,1,0]
+Output: 1
+
+Note:
+
+    3 <= A.length <= 10000
+    0 <= A[i] <= 10^6
+    A is a mountain, as defined above.
+

852/run.sh

+#!/bin/bash
+
+python3 main.py