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New problem done

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Lachlan Jacob 5 jaren geleden
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d56b66114f
3 gewijzigde bestanden met toevoegingen van 29 en 0 verwijderingen
  1. 16
    0
      problems/58/main.py
  2. 10
    0
      problems/58/problem.txt
  3. 3
    0
      problems/58/run.sh

+ 16
- 0
problems/58/main.py Bestand weergeven

@@ -0,0 +1,16 @@
class Solution:
def lengthOfLastWord(self, s: str) -> int:
s = s.strip()
for i in range(len(s) - 1, -1, -1):
if s[i] == " ":
print("Found space at", i, len(s) - 1)
if i == len(s) - 1:
return 0
else:
return len(s[i+1:])
return len(s)

s = Solution()
print("Expected: 0")
print("Got:", s.lengthOfLastWord("Test"))

+ 10
- 0
problems/58/problem.txt Bestand weergeven

@@ -0,0 +1,10 @@
Given a string s consists of upper/lower-case alphabets and empty space characters ' ', return the length of last word (last word means the last appearing word if we loop from left to right) in the string.

If the last word does not exist, return 0.

Note: A word is defined as a maximal substring consisting of non-space characters only.

Example:

Input: "Hello World"
Output: 5

+ 3
- 0
problems/58/run.sh Bestand weergeven

@@ -0,0 +1,3 @@
#!/bin/bash

python3 main.py

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