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master
Lachlan Jacob 5 年前
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d56b66114f
共有 3 个文件被更改,包括 29 次插入0 次删除
  1. 16
    0
      problems/58/main.py
  2. 10
    0
      problems/58/problem.txt
  3. 3
    0
      problems/58/run.sh

+ 16
- 0
problems/58/main.py 查看文件

@@ -0,0 +1,16 @@
class Solution:
def lengthOfLastWord(self, s: str) -> int:
s = s.strip()
for i in range(len(s) - 1, -1, -1):
if s[i] == " ":
print("Found space at", i, len(s) - 1)
if i == len(s) - 1:
return 0
else:
return len(s[i+1:])
return len(s)

s = Solution()
print("Expected: 0")
print("Got:", s.lengthOfLastWord("Test"))

+ 10
- 0
problems/58/problem.txt 查看文件

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Given a string s consists of upper/lower-case alphabets and empty space characters ' ', return the length of last word (last word means the last appearing word if we loop from left to right) in the string.

If the last word does not exist, return 0.

Note: A word is defined as a maximal substring consisting of non-space characters only.

Example:

Input: "Hello World"
Output: 5

+ 3
- 0
problems/58/run.sh 查看文件

@@ -0,0 +1,3 @@
#!/bin/bash

python3 main.py

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