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Added some more problems and structure

master
Lachlan Jacob před 5 roky
rodič
revize
76028e5562
15 změnil soubory, kde provedl 73 přidání a 1 odebrání
  1. 3
    0
      125/problem.txt
  2. 2
    0
      175/main.sql
  3. 29
    0
      175/problem.txt
  4. 3
    0
      175/run.sh
  5. 1
    0
      176/main.sql
  6. 1
    0
      176/problem.txt
  7. 3
    0
      176/run.sh
  8. 1
    0
      182/main.sql
  9. 1
    0
      182/problem.txt
  10. 3
    0
      182/run.sh
  11. 15
    0
      66/main.py
  12. 5
    0
      66/problem.txt
  13. 3
    0
      66/run.sh
  14. 2
    1
      README.md
  15. 1
    0
      all.sh

+ 3
- 0
125/problem.txt Zobrazit soubor

@@ -0,0 +1,3 @@
Given a string, determine if it is a palindrome, considering only alphanumeric characters and ignoring cases.

Note: For the purpose of this problem, we define empty string as valid palindrome.

+ 2
- 0
175/main.sql Zobrazit soubor

@@ -0,0 +1,2 @@
SELECT FirstName, LastName, City, State FROM Person
LEFT JOIN Address ON Person.PersonId = Address.PersonId;

+ 29
- 0
175/problem.txt Zobrazit soubor

@@ -0,0 +1,29 @@
Table: Person

+-------------+---------+
| Column Name | Type |
+-------------+---------+
| PersonId | int |
| FirstName | varchar |
| LastName | varchar |
+-------------+---------+
PersonId is the primary key column for this table.

Table: Address

+-------------+---------+
| Column Name | Type |
+-------------+---------+
| AddressId | int |
| PersonId | int |
| City | varchar |
| State | varchar |
+-------------+---------+
AddressId is the primary key column for this table.


Write a SQL query for a report that provides the following information for each person in the Person table, regardless if there is an address for each of those people:

FirstName, LastName, City, State



+ 3
- 0
175/run.sh Zobrazit soubor

@@ -0,0 +1,3 @@
#!/bin/bash

echo "Can't be botherd making this into a test"

+ 1
- 0
176/main.sql Zobrazit soubor

@@ -0,0 +1 @@
SELECT MAX(Salary) AS SecondHighestSalary FROM Employee WHERE Salary != (SELECT MAX(Salary) FROM Employee);

+ 1
- 0
176/problem.txt Zobrazit soubor

@@ -0,0 +1 @@
Write a SQL query to get the second highest salary from the Employee table.

+ 3
- 0
176/run.sh Zobrazit soubor

@@ -0,0 +1,3 @@
#!/bin/bash

echo "Can't be botherd making this into a test"

+ 1
- 0
182/main.sql Zobrazit soubor

@@ -0,0 +1 @@
SELECT Email FROM (SELECT Email, COUNT(Email) AS cnt FROM Person GROUP BY Email) AS b WHERE cnt > 1;

+ 1
- 0
182/problem.txt Zobrazit soubor

@@ -0,0 +1 @@
Write a SQL query to find all duplicate emails in a table named Person

+ 3
- 0
182/run.sh Zobrazit soubor

@@ -0,0 +1,3 @@
#!/bin/bash

echo "Can't be botherd making this into a test"

+ 15
- 0
66/main.py Zobrazit soubor

@@ -0,0 +1,15 @@
class Solution:
def plusOne(self, digits):
numberString = ""
for n in digits:
numberString += str(n)

number = int(numberString) + 1
final = []
for digit in str(number):
final.append(int(digit))
return final

s = Solution()
print("Expected: [1, 2, 4]")
print("Got:", str(s.plusOne([1, 2, 3])))

+ 5
- 0
66/problem.txt Zobrazit soubor

@@ -0,0 +1,5 @@
Given a non-empty array of digits representing a non-negative integer, plus one to the integer.

The digits are stored such that the most significant digit is at the head of the list, and each element in the array contain a single digit.

You may assume the integer does not contain any leading zero, except the number 0 itself.

+ 3
- 0
66/run.sh Zobrazit soubor

@@ -0,0 +1,3 @@
#!/bin/bash

python3 main.py

+ 2
- 1
README.md Zobrazit soubor

@@ -8,8 +8,9 @@ Aiming for one a day, to try be a little consistent.

Folder Names will Be Puzzle Numbers and contain:

- `problem.txt` - A plain text file with a problem description.
- `main.<language extension>` will be the code submitted. (Some code may have to be modified to run outside of LeetCode's driver).
- run.sh (This will contain a bash scipt to run/compile+run the code.
- `run.sh` (This will contain a bash scipt to run/compile+run the code.

## Necessary Dependencies


+ 1
- 0
all.sh Zobrazit soubor

@@ -2,6 +2,7 @@

for f in *; do
if [ -d ${f} ]; then
echo ""
echo "Running Problem: $f"
cd $f
./run.sh

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