Pārlūkot izejas kodu

Added some more problems and structure

master
Lachlan Jacob pirms 5 gadiem
vecāks
revīzija
76028e5562
15 mainītis faili ar 73 papildinājumiem un 1 dzēšanām
  1. 3
    0
      125/problem.txt
  2. 2
    0
      175/main.sql
  3. 29
    0
      175/problem.txt
  4. 3
    0
      175/run.sh
  5. 1
    0
      176/main.sql
  6. 1
    0
      176/problem.txt
  7. 3
    0
      176/run.sh
  8. 1
    0
      182/main.sql
  9. 1
    0
      182/problem.txt
  10. 3
    0
      182/run.sh
  11. 15
    0
      66/main.py
  12. 5
    0
      66/problem.txt
  13. 3
    0
      66/run.sh
  14. 2
    1
      README.md
  15. 1
    0
      all.sh

+ 3
- 0
125/problem.txt Parādīt failu

@@ -0,0 +1,3 @@
Given a string, determine if it is a palindrome, considering only alphanumeric characters and ignoring cases.

Note: For the purpose of this problem, we define empty string as valid palindrome.

+ 2
- 0
175/main.sql Parādīt failu

@@ -0,0 +1,2 @@
SELECT FirstName, LastName, City, State FROM Person
LEFT JOIN Address ON Person.PersonId = Address.PersonId;

+ 29
- 0
175/problem.txt Parādīt failu

@@ -0,0 +1,29 @@
Table: Person

+-------------+---------+
| Column Name | Type |
+-------------+---------+
| PersonId | int |
| FirstName | varchar |
| LastName | varchar |
+-------------+---------+
PersonId is the primary key column for this table.

Table: Address

+-------------+---------+
| Column Name | Type |
+-------------+---------+
| AddressId | int |
| PersonId | int |
| City | varchar |
| State | varchar |
+-------------+---------+
AddressId is the primary key column for this table.


Write a SQL query for a report that provides the following information for each person in the Person table, regardless if there is an address for each of those people:

FirstName, LastName, City, State



+ 3
- 0
175/run.sh Parādīt failu

@@ -0,0 +1,3 @@
#!/bin/bash

echo "Can't be botherd making this into a test"

+ 1
- 0
176/main.sql Parādīt failu

@@ -0,0 +1 @@
SELECT MAX(Salary) AS SecondHighestSalary FROM Employee WHERE Salary != (SELECT MAX(Salary) FROM Employee);

+ 1
- 0
176/problem.txt Parādīt failu

@@ -0,0 +1 @@
Write a SQL query to get the second highest salary from the Employee table.

+ 3
- 0
176/run.sh Parādīt failu

@@ -0,0 +1,3 @@
#!/bin/bash

echo "Can't be botherd making this into a test"

+ 1
- 0
182/main.sql Parādīt failu

@@ -0,0 +1 @@
SELECT Email FROM (SELECT Email, COUNT(Email) AS cnt FROM Person GROUP BY Email) AS b WHERE cnt > 1;

+ 1
- 0
182/problem.txt Parādīt failu

@@ -0,0 +1 @@
Write a SQL query to find all duplicate emails in a table named Person

+ 3
- 0
182/run.sh Parādīt failu

@@ -0,0 +1,3 @@
#!/bin/bash

echo "Can't be botherd making this into a test"

+ 15
- 0
66/main.py Parādīt failu

@@ -0,0 +1,15 @@
class Solution:
def plusOne(self, digits):
numberString = ""
for n in digits:
numberString += str(n)

number = int(numberString) + 1
final = []
for digit in str(number):
final.append(int(digit))
return final

s = Solution()
print("Expected: [1, 2, 4]")
print("Got:", str(s.plusOne([1, 2, 3])))

+ 5
- 0
66/problem.txt Parādīt failu

@@ -0,0 +1,5 @@
Given a non-empty array of digits representing a non-negative integer, plus one to the integer.

The digits are stored such that the most significant digit is at the head of the list, and each element in the array contain a single digit.

You may assume the integer does not contain any leading zero, except the number 0 itself.

+ 3
- 0
66/run.sh Parādīt failu

@@ -0,0 +1,3 @@
#!/bin/bash

python3 main.py

+ 2
- 1
README.md Parādīt failu

@@ -8,8 +8,9 @@ Aiming for one a day, to try be a little consistent.

Folder Names will Be Puzzle Numbers and contain:

- `problem.txt` - A plain text file with a problem description.
- `main.<language extension>` will be the code submitted. (Some code may have to be modified to run outside of LeetCode's driver).
- run.sh (This will contain a bash scipt to run/compile+run the code.
- `run.sh` (This will contain a bash scipt to run/compile+run the code.

## Necessary Dependencies


+ 1
- 0
all.sh Parādīt failu

@@ -2,6 +2,7 @@

for f in *; do
if [ -d ${f} ]; then
echo ""
echo "Running Problem: $f"
cd $f
./run.sh

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