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Added some more problems and structure

master
Lachlan Jacob 5 年之前
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共有 15 個文件被更改,包括 73 次插入1 次删除
  1. 3
    0
      125/problem.txt
  2. 2
    0
      175/main.sql
  3. 29
    0
      175/problem.txt
  4. 3
    0
      175/run.sh
  5. 1
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      176/main.sql
  6. 1
    0
      176/problem.txt
  7. 3
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      176/run.sh
  8. 1
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      182/main.sql
  9. 1
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      182/problem.txt
  10. 3
    0
      182/run.sh
  11. 15
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      66/main.py
  12. 5
    0
      66/problem.txt
  13. 3
    0
      66/run.sh
  14. 2
    1
      README.md
  15. 1
    0
      all.sh

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125/problem.txt 查看文件

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Given a string, determine if it is a palindrome, considering only alphanumeric characters and ignoring cases.

Note: For the purpose of this problem, we define empty string as valid palindrome.

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175/main.sql 查看文件

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SELECT FirstName, LastName, City, State FROM Person
LEFT JOIN Address ON Person.PersonId = Address.PersonId;

+ 29
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175/problem.txt 查看文件

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Table: Person

+-------------+---------+
| Column Name | Type |
+-------------+---------+
| PersonId | int |
| FirstName | varchar |
| LastName | varchar |
+-------------+---------+
PersonId is the primary key column for this table.

Table: Address

+-------------+---------+
| Column Name | Type |
+-------------+---------+
| AddressId | int |
| PersonId | int |
| City | varchar |
| State | varchar |
+-------------+---------+
AddressId is the primary key column for this table.


Write a SQL query for a report that provides the following information for each person in the Person table, regardless if there is an address for each of those people:

FirstName, LastName, City, State



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175/run.sh 查看文件

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#!/bin/bash

echo "Can't be botherd making this into a test"

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176/main.sql 查看文件

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SELECT MAX(Salary) AS SecondHighestSalary FROM Employee WHERE Salary != (SELECT MAX(Salary) FROM Employee);

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176/problem.txt 查看文件

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Write a SQL query to get the second highest salary from the Employee table.

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176/run.sh 查看文件

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#!/bin/bash

echo "Can't be botherd making this into a test"

+ 1
- 0
182/main.sql 查看文件

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SELECT Email FROM (SELECT Email, COUNT(Email) AS cnt FROM Person GROUP BY Email) AS b WHERE cnt > 1;

+ 1
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182/problem.txt 查看文件

@@ -0,0 +1 @@
Write a SQL query to find all duplicate emails in a table named Person

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182/run.sh 查看文件

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#!/bin/bash

echo "Can't be botherd making this into a test"

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- 0
66/main.py 查看文件

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class Solution:
def plusOne(self, digits):
numberString = ""
for n in digits:
numberString += str(n)

number = int(numberString) + 1
final = []
for digit in str(number):
final.append(int(digit))
return final

s = Solution()
print("Expected: [1, 2, 4]")
print("Got:", str(s.plusOne([1, 2, 3])))

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66/problem.txt 查看文件

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Given a non-empty array of digits representing a non-negative integer, plus one to the integer.

The digits are stored such that the most significant digit is at the head of the list, and each element in the array contain a single digit.

You may assume the integer does not contain any leading zero, except the number 0 itself.

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66/run.sh 查看文件

@@ -0,0 +1,3 @@
#!/bin/bash

python3 main.py

+ 2
- 1
README.md 查看文件

@@ -8,8 +8,9 @@ Aiming for one a day, to try be a little consistent.

Folder Names will Be Puzzle Numbers and contain:

- `problem.txt` - A plain text file with a problem description.
- `main.<language extension>` will be the code submitted. (Some code may have to be modified to run outside of LeetCode's driver).
- run.sh (This will contain a bash scipt to run/compile+run the code.
- `run.sh` (This will contain a bash scipt to run/compile+run the code.

## Necessary Dependencies


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all.sh 查看文件

@@ -2,6 +2,7 @@

for f in *; do
if [ -d ${f} ]; then
echo ""
echo "Running Problem: $f"
cd $f
./run.sh

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