소스 검색

Added some more problems and structure

master
Lachlan Jacob 5 년 전
부모
커밋
76028e5562
15개의 변경된 파일73개의 추가작업 그리고 1개의 파일을 삭제
  1. 3
    0
      125/problem.txt
  2. 2
    0
      175/main.sql
  3. 29
    0
      175/problem.txt
  4. 3
    0
      175/run.sh
  5. 1
    0
      176/main.sql
  6. 1
    0
      176/problem.txt
  7. 3
    0
      176/run.sh
  8. 1
    0
      182/main.sql
  9. 1
    0
      182/problem.txt
  10. 3
    0
      182/run.sh
  11. 15
    0
      66/main.py
  12. 5
    0
      66/problem.txt
  13. 3
    0
      66/run.sh
  14. 2
    1
      README.md
  15. 1
    0
      all.sh

+ 3
- 0
125/problem.txt 파일 보기

@@ -0,0 +1,3 @@
Given a string, determine if it is a palindrome, considering only alphanumeric characters and ignoring cases.

Note: For the purpose of this problem, we define empty string as valid palindrome.

+ 2
- 0
175/main.sql 파일 보기

@@ -0,0 +1,2 @@
SELECT FirstName, LastName, City, State FROM Person
LEFT JOIN Address ON Person.PersonId = Address.PersonId;

+ 29
- 0
175/problem.txt 파일 보기

@@ -0,0 +1,29 @@
Table: Person

+-------------+---------+
| Column Name | Type |
+-------------+---------+
| PersonId | int |
| FirstName | varchar |
| LastName | varchar |
+-------------+---------+
PersonId is the primary key column for this table.

Table: Address

+-------------+---------+
| Column Name | Type |
+-------------+---------+
| AddressId | int |
| PersonId | int |
| City | varchar |
| State | varchar |
+-------------+---------+
AddressId is the primary key column for this table.


Write a SQL query for a report that provides the following information for each person in the Person table, regardless if there is an address for each of those people:

FirstName, LastName, City, State



+ 3
- 0
175/run.sh 파일 보기

@@ -0,0 +1,3 @@
#!/bin/bash

echo "Can't be botherd making this into a test"

+ 1
- 0
176/main.sql 파일 보기

@@ -0,0 +1 @@
SELECT MAX(Salary) AS SecondHighestSalary FROM Employee WHERE Salary != (SELECT MAX(Salary) FROM Employee);

+ 1
- 0
176/problem.txt 파일 보기

@@ -0,0 +1 @@
Write a SQL query to get the second highest salary from the Employee table.

+ 3
- 0
176/run.sh 파일 보기

@@ -0,0 +1,3 @@
#!/bin/bash

echo "Can't be botherd making this into a test"

+ 1
- 0
182/main.sql 파일 보기

@@ -0,0 +1 @@
SELECT Email FROM (SELECT Email, COUNT(Email) AS cnt FROM Person GROUP BY Email) AS b WHERE cnt > 1;

+ 1
- 0
182/problem.txt 파일 보기

@@ -0,0 +1 @@
Write a SQL query to find all duplicate emails in a table named Person

+ 3
- 0
182/run.sh 파일 보기

@@ -0,0 +1,3 @@
#!/bin/bash

echo "Can't be botherd making this into a test"

+ 15
- 0
66/main.py 파일 보기

@@ -0,0 +1,15 @@
class Solution:
def plusOne(self, digits):
numberString = ""
for n in digits:
numberString += str(n)

number = int(numberString) + 1
final = []
for digit in str(number):
final.append(int(digit))
return final

s = Solution()
print("Expected: [1, 2, 4]")
print("Got:", str(s.plusOne([1, 2, 3])))

+ 5
- 0
66/problem.txt 파일 보기

@@ -0,0 +1,5 @@
Given a non-empty array of digits representing a non-negative integer, plus one to the integer.

The digits are stored such that the most significant digit is at the head of the list, and each element in the array contain a single digit.

You may assume the integer does not contain any leading zero, except the number 0 itself.

+ 3
- 0
66/run.sh 파일 보기

@@ -0,0 +1,3 @@
#!/bin/bash

python3 main.py

+ 2
- 1
README.md 파일 보기

@@ -8,8 +8,9 @@ Aiming for one a day, to try be a little consistent.

Folder Names will Be Puzzle Numbers and contain:

- `problem.txt` - A plain text file with a problem description.
- `main.<language extension>` will be the code submitted. (Some code may have to be modified to run outside of LeetCode's driver).
- run.sh (This will contain a bash scipt to run/compile+run the code.
- `run.sh` (This will contain a bash scipt to run/compile+run the code.

## Necessary Dependencies


+ 1
- 0
all.sh 파일 보기

@@ -2,6 +2,7 @@

for f in *; do
if [ -d ${f} ]; then
echo ""
echo "Running Problem: $f"
cd $f
./run.sh

Loading…
취소
저장